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गर्ने भन्ने हनुमान् पगरी गुथ्ने ढेडुः  दिनभरि बिरुवा चाहिँ मैले रोपेँ तर बुबाको अगाडि भाइ .....

म ऋत्विकलाई क्रिकेट खेलाउँछु । यसको विचार कस्तो छ ? यसलाई कफी या चिया के ल्याऊँ ? हजुर दाँत किन .....

(क) उ बुटबल घुम्न जान्छ । (ख) तिमीहरु अन्धकारमा हरायौ .....

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You know, exercise maintains our physical fitness. It maintains our overall health and wellness. If then what is physical exercise? Physical exercise is the performance of some activity. It is done in order to develop or maintain .....

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Plants which body is thallus type I.e without leaves, stem and root are thallophytes. It includes algae, fungi etc. One example of thallophyte is .....

  Here, join A&H  and C&E. Now, in △BCE  & △ ABH,        BE = BH(S)                       [ Given]       .....

The below-given picture is of one of the rituals practiced in Nepali society. It is known as Bratabandha. It is a process of confirming a young man as an .....

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The province no 2 and the province no 5 does not contain the higher Himalayan region. These provinces are connected to India only; while the other provinces id connected both to India and China. The province no 2 contains only the Terai .....

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The angles which occupy the same relative position at each intersection where a straight line crosses two others. If the two lines are parallel, the corresponding angles are .....

30 - 10 + 1/3 ⨉ (18/2 + 3 ⨉ 2) Using BODMAS = 30 - 10 + 1/3 ⨉ (9 + 6) = 30 - 10 + 1/3 (15) = 30 - 10 + 5  = .....

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Ther are many times and situations when we get lost. We sometimes fall into the bad habit and get lost on our way to be a good person. When we find that we are heading in the wrong direction; we should seek help from our seniors. We should not .....

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13m2 - 11 = (√13 m)2 - (√11)2 = (√13 m + √11) (√13 m- .....

Draw any three triangles as ABC using scale with different measure where side AC is has greater length than side AB. Tabulate the reading by measuring with  scale  and protector. And write the .....

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The scalar matrix is basically a square matrix, whose all off-diagonal elements are zero and all on-diagonal elements are equal. Thus from the given matrix we can write, 3a = 0   [since 3a is off-digonal element] or, a = 0 2b - a +4 = .....

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Here, Square of (3x - 7y)           = (3x - 7y) 2            = (3x - 7y) (3x - 7y)           = 3x(3x - 7y) - 7y (3x - 7y)       .....

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Here is how to bisect the angle BAC Place the point of the compass on A, and swing an arc ED. Then, with D as center and DE as radius, draw an arc. Keeping the same radius and with E as center, draw an arc that will .....

Here,  Area of //gm ABEF = Area of //gm ABCD    [ On same base & between same //s.] or,  BE ⨯ FT = AB ⨯BC                  .....

We know, Area of square = 1/2 ⨯ d2 = 1/2 ⨯ SQ2 = 1/2 ⨯64cm2  = 32cm2       [Area of square = 1/2 .....

Here,  i) △XMZ = △WMZ  [ on same base & same //s.] ii) △XMY = 1/2 of △ XMZ     [ XY is median.] iii) △WPZ = 1/2 of △ WMZ.    [ PZ is median.] Now combine these three equations .....

Given, SQ//RT area of △SQT is 12 cm2 and 2.Ar. of △PSQ = 3 Ar. of △SQT. We know, △SQT = △SQR = 12cm2  [ on same base & between same //s.] △PQS = 3/2 of △SQT = 18cm2   [ 2.Ar. .....

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The weight of an object is defined as Weight=mass of the bady × acceleration due to gravity = mg. And the acceleration deue to gravity is, Acceleration due to gravity (g)= MG/ R2. So, you can see that g is inversly proportional to the .....

Join S & B and  A& R. Then, try to show area of △SAB = △ SAR. Finally, SA//BR. Since if the area of triangles on same base SA & between same //s SA & BR are eqaul, the lines are .....

Here, you can join B&Q,   Now, △QBP=1/2 △PQR,  [ Since median BQ bisects the  △PQR.]     △ABQ=1/2 △QBP      [ Since median BA bisects the  △QBP.]   .....