Students and Teachers Forum

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Here,        xcotA.tan(90+A) = tan(90+A).cot(180-A)+xsec(90+A).cosecA or,  xcotA.(-cotA) = -cotA.(-cotA)+x(-cosecA).cosecA or, -xcot2A = cot2A - xcosec2A or,  xcosec2A - xcot2A = cot2A or,  x(cosec2A-cot2A) = .....

The vehicles that help us travel on land are called land .....

महल पस .....

कलश भर .....

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१. लामखुट्टे २. लट्टे ३. खट्टे ४. बत्ती ५. .....

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We see the moon and the stars at .....

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Here, RHS  = (2cos2A - 1)(2cos2A  + 1)(2cos4A - 1)(2cos8A - 1)  = {(2cos2A)2 - 12}(2cos4A - 1)(2cos8A - 1)  = (4cos22A - 1)(2cos4A - 1)(2cos8A - 1)  = {2(cos4A + 1)- 1}(2cos4A - 1)(2cos8A - 1)  .....

Here, we have been given a percentage. We have been asked to express into lower term of fraction. At first let us write down given information: Given,  10%  To express percentage in fraction, we should divide percentage by 100 and remove % .....

The two examples of side effect due to drinking are: i)   Liver damage ii)  Road .....

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ऊ बजार गयो .....

The state has to make proper policies including marginalized and minorities and need to implement various programmes in order to increase .....

Here, LHS =(1 - cos π/8)(1 - cos 3π/8)(1 - cos 5π/8)(1 - cos 7π/8) = (1 - cos π/8)(1 - cos 3π/8)(1 + cos 3π/8)(1 + cos π/8), [since cos(π - A) = -cos A.] = (1 - cos² π/8)(1 - cos² 3π/8) = (1 - .....

घर बस .....

We know that there are more than 6000 rivers in Nepal. They are now being polluted disappeared due to pollutions. So, the following types of measures should be taken for the protection of our rivers from .....

Taking, LHS  = 2tan450-A1+ tan2(450-A      We know,  2tanA1+tan2A=sin2A Then, = sin2(450 - A) = sin( 90o - 2A) = cos2A  LHS = RHS proved. .....

Here, LHS = (cot2A + tan2A)/(cot2A - tan2A) = (1/tan2A + tan2A)/(1/tan2A - tan2A)   [ ∵ cotX = 1/tanX.] = {(1 + tan22A)/tan2A}/{(1 - tan22A)/tan2A} = (1 + tan22A)/{(1 - tan22A) = 1/{(1 - tan22A)/(1 + tan22A)} = .....

Jonathan .....

We know thw formula, tan 2X = 2tanX / (1- tan²X)

LHS = tanA + 2tan2A + 4/(tan4A)

= tanA + 2tan2A + {4/ (2tan2A)/(1-tan²2A)}

= tanA + 2tan2A + 4(1-tan²2A) / 2tan2A

= tanA + 2tan2A + .....

चकचक नगर .....

नरम बन .....

पर सर .....

Here, LHS = (1 + cosA)/(1 - cosA) = (1 + 2cos2A/2 - 1)/(1 - 1 + 2sin2A/2)   [ Since, cosA = 2cos2A/2 - 1 and cosA = 1 - 2sin2A/2.] = 2cos2A/2 / 2sin2A/2 = .....

टप लगाऊ .....

1. Chicken 2. Horse 3. Donkey 4. Cow 5. .....

घरसँग आँगन जोडिएको छ .....

Here,  A,B& C are angles of a triangle. So,      A+B+C =180o or,A+B = 180 - C. Operating both sides by tan,we get       tan(A+B) = tan(180-C) or, tan(A+B) = - tanC or, tan(A+B) + tanC = 0       .....

Here, we have to convert the kilometre value of length into .....

Here, LHS = sin2A cos2B - sin2B cos2A  = (1 - cos2A)(2cos2B - 1) - (1 - cos2B)(2cos2A - 1)   [ Since, sin2X = 1 - cos2X and cos2X = 2cos2X - 1).] Opening bracket we get = 2cos2B - 1 - 2cos2A.cos2B + cos2A -{2cos2A - 1 - .....

Here, LHS = Tan (π/4 + A/2) - tan (A/2 - π/4 ) = Tan (π/4 + A/2) - tan (π/4 - A/2) = Sin(π/4 + A/2)/cos(π/4 + A/2) + sin(π/4 - A/2)/cos(π/4 - A/2) = {sin(π/4 + A/2) cos(π/4 - A/2) + cos(π/4 + .....