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Solution : Area of equilateral triangle A = 25√3 cm2 Length  l = ? We know, A = (√3 l2 ) / 4 = √3 * l2 / 4 or, 25 √3 = √3 / 4 * l2 or, l2 = 100 or, l2 = 102 or, l = 10 Thus, the length of its side is 10 .....

Area of Isosceles Triangle Using Only Sides = ½[√(a2 − b2 /4) × b]

Here,

Solution : base ( BC) = 10 cm height (AD) = 8 cm Area A = ? we know,  A = 1/2 * BC * AD = 1/2 * 10 cm  * 8 cm = .....

Let,

Derivation for Isosceles Triangle Area Using Heron’s Formula

The area of an isosceles triangle can be .....

Now,

Area of Triangle = ½ × base × height

Here, base = a, and height = h

Now, apply Pythagoras Theorem in the triangle.

a2 = h2 + (a/2)2

⇒ h2=a2–a2/4

⇒ .....

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area of isosceles triangle = y/2 × √(x2 − .....

Length of equilateral triangle = p cm Area  = (√3/4) p2 .....

Area of triangle = 1/2 * base * height = 1/2 * a * b .....

Area of triangle = 1/2 * base * height = 1/2 * x * y .....

Please replace 30 by 31 in first equation of .....

Here, given  radius of football (r) = 9cm Football is a sphere We know that, Volume of sphere (V) =  4/3 πr^3   Can you calculate the volume of football .....

Circle have area and Spheres have volume. The are of circle is π * r^2 The volume of Sphere with radius of r is  (4/3) * π * r^3.      .....

Solution : Initial price  D = Rs. 240,000 Rate for 3 years  = 5%, 10%, 15% Price after 3 years DT = ? We know, DT = D [ ( 1 - R1/ 100) ( 1 - R2/ 100) ( 1 - R3/ 100)]       = 240000 ( 1 - 5/100)(1 - 10/100)(1 - .....

Solution : Initial price  D = Rs. 75,000 Rate for 3 years  = 2%, 4%, 5% Price after 3 years DT = ? We know, DT = D [ ( 1 - R1/ 100) ( 1 - R2/ 100) ( 1 - R3/ 100)]       = 75000 ( 1 - 2/100)(1 - 4/100)(1 - .....

A quartile is a group of values and/or means that divide a data set into quarters, or groups of four. Do not be confused here; a quartile is a value, not a group of numbers. Think of a quartile as a cut off point for each group. A group has to start .....

Solution : Inital price D = Rs.1,20,000 Present price DT = Rs.86,700 Rate R = 15% Time T = ? We know, DT = D ( 1 - R/100)T or, 86,700 = 120000 ( 1 - 15/100)T or, 0.7225 = 0.85T or, 0.852 = 0.85T or, T = 2 Thus, She used the scooter for 2 .....

Solution : Initial Price D = Rs.400000 Present price DT = Rs.196000 Rate of depreciation R = 30% Time T = ? We know, DT = D ( 1 - R/100)T or, 196000 = 400000 ( 1 - 30/100)T or, 0.49= 0.7T or, 0.72 = 0.7T or, T = 2 years Thus, the factory was bought .....

Solution : Initial Price S = Rs.12,50,000 Time T = 3 years Rate R = 12% Price depreciated DT = ? We know, DT = D ( 1 - R/100)T       = 1250000 ( 1 - 12/100)3  = 1250000 x 0.681472 = .....

Solution : Price after 3 years PT = Rs.13,718 Time T = 3 years Rate of depreciation R = 5% Initial price P = ? We know, PT = P ( 1 -R/100)T or, 13718 = P ( 1 - 5/100)3 or, 13718 = P x 0.857375 or, P = Rs.16000 Thus, She paid Rs.16000 at that .....

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Solution : Initial price P = Rs.40000 Rate R = 10% Time T = 2 years Price after 2 years PT = ? we know, PT = P ( 1 - R/100)T       = 40000 ( 1 - 10/100)2       = 40000 x .....

Solution : Original price D = Rs.50,000 Present price DT = Rs.42,500 Time T = 1 year Rate of depreciation R = ? We know, DT = D ( 1 - R/100)T or, 42500 = 50000 ( 1 - R/100) or, 0.85 = 1 - R/100 or, - 0.15 = - R/100 or, R = 15% Thus, the .....

Solution : Rate of depreciation R = 10% Price after a year DT = Rs. 5,80,500 Time T = 1 year Original price D = ? We know, DT = D ( 1 - R/100)T or, 580500 = D ( 1 - 10/100) or, 580500 = D * 90/100 or, D = 645000 so, the original value is .....

We are human being and living thing. Its our Life cycle which includes birth,growth and .....

Solution : Initial value P = Rs. 260000 Rate of depreciation R = 5% Time T = 1 year Price after a year PT = ? We know, PT = P (1-R/100)T       = 260000(1-5/100)1         = Rs. .....

Solution : Original value = P Time = T = 3 years Rate of depreciation = R1% , R2% , R3% Depriciated value of a vehicle DT = D [( 1 - R1/100 )( 1 - R2/100 )( 1 - R3/100 .....

Solution : Original value = P Time = T Rate of depreciation = R% Depriciated value of a vehicle DT = D ( 1 - R/100 .....

Solution : Initial value P Rate of depreciation R% Time T year Amount of depreciation PT = P .....

Solution : Original value = P Time = T Rate of depreciation = R% Depriciated value of a vehicle DT = D ( 1 - R/100 .....

Solution : Initial population P = 9765625 Rate of depreciation R = 4% Time T = 2 year Final population PT = ? We know, PT = P (1+R/100)T       = 9765625(1+4/100)2        = .....

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Solution : Initial Polulation in 2071 , P = 1,80,000 Population in 2073 , PT = 2,39,580 Time T = 3 years Rate R = ? We know, PT = P (1+R/100)T or, 2,39,580 = 1,80,000 (1+R/100)3 or, 239580/180000 = (1+R/100)3 or, 1.331 = (1+R/100)3 or, .....

Population at present P = 80,000 Population after two years PT = 88,200 Time T = 2 years Rate R = ? we know, PT = P ( 1 + R/100 )T or, 88200 = 80000 ( 1 + R/100 ) 2 or, 1.1025 =  ( 1 + R/100 ) 2 or, 1.052 = ( 1 + R/100 ) 2 or, 1.05 = ( .....

Solution : Solution : Initial Population P = 96,250 Population after T years PT = 104104 Rate R = 4% Then  , PT = P [(1+R/100)T] or, 104104 = 96250 (1+4/100)T or, 104104/96250 (1.04)T or, 1.0816 = 1.04T or, 1.042 = 1.04T or, T = 2 .....

SI unit of heat is .....

Initial population  = P Rate of population = R% Time = T years Increased Population PT = P [ .....

Solution : Initial population = P Rate = R% Time = T years Population of a region after T years PT = P [ (1 + .....

Some of the major festivals celebrated by hindus are: Dashain Tihar Chhath Holi Teej ( by hindu women) and .....

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Ecosystem is a community or group of living organisms that live in and interact with each other in a specific environment. It is made of both boitic and abiotic components of the environment.

Solution : Principal P = Rs.40,000 Compound Interest CI = Rs.6,305 For Rate, P = Rs.1 , I = Rs.5/100 , T = 1 year , then, R = (I *100)/(P * T) = 5% so, Rate R = 5% Time T = ? we know, CI = P [(1+R/100)T  - 1] = 40000[(1+5/100)T - 1] or, .....

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Well, cooperatives are the joint venture of the people who have shared goals. The cooperatives are established mostly for the support of the local people for running their economic activities. Robert Owen (1771–1858), a Welshman, who made .....

Solution : Principal P = Rs.25,000 Time T = 2 years Rate R1 = 10% Rate R2 = 12% Compound Amount CA = ? we know, CA = P[(1+R1 / 100) (1 + R2 / 100 )] = 25000 (1+10/100)(1+12/100) = 25000 * 110/100 * 112/100 = 25000 * 1.1 * 1.12 = .....

Yes we can survive in the world without measurement.    Food ,shelter and air are our basic needs to survive. But we have to face difficulties while measuring weight , length and other measurement for our day to day .....