Students and Teachers Forum
Globalization is the process of integration of the entire population of the world in such a manner that an event in one nation has an impact across the world. Globalization has assisted human in many ways. Some of them are: easy access .....
The answers are .....
Answers 1. a 2. in 3. didn't he 4. were not 5. was hit 6. took 7. what her name was 8. so 9. would have died 10. to .....
The fertility rate and the mortality rate of the developed countries are 11 and 10 (in million). The fertility rate and the mortality rate of the least developed countries are 35 and 11 (in million). The above data shows that the population growth .....
राष्ट्रिय जनगणना, २०६८ अनुसार, नेपालमा १० धर्म, १२५ जाती र १२३ भाषा छन् । तामाङ, लिम्बू, राई, .....
नेपाललाई हिमाली, पहाडी र तराइ गरी भौगोलिक रुपमा ३ भागमा बिभाजन गरिएको छ । बिभिन्न क्षेत्रको .....
इतिहासका स्रोतहरुको संरक्षणका उपायहरू सम्बन्धमा निम्नलिखित बुँदामा प्रस्तुत गर्न .....
There are many causes for the outbreak of the Second World War. .....
Let f(x) = xn + an To check whether (x + a ) is a factor of xn + an or not, f(-a) = 0 Checking, f(-a) = (-a)n + (a)n = (-1 . a)n + an = (-1)n . an + an Since n is odd, (-1)n = -1 So, .....
नेपालमा परम्परागत निर्वाहमुखी खेतीले प्रश्रय पाउँदै आएको छ । अधिकांश नेपालीले कृषिकार्य .....
Join O&R and O & S as in figure. Here, PQ is the diameter and RS is a chord. We need to prove PQ>RS. OP = OQ = OR = OS [ Radii of circle.] In triangle ORS, OR + OS>RS. [ .....
That is called sin rule of triangle. a/sinA = b/sinB = .....
Environmental sanitation" means the art and science of applying sanitary, biological and physical science principles and knowledge to improve and control the environment and factors therein for the protection of the health .....
कृपया प्रश्न स्पष्ट लेखिदिनुहोला .....
Here, y = f(x) = 2x2 + 3 and range = {3, 5} = y. Put y = 3, 3 = 2x2 + 3 or, x2 = 0 or, x = 0. Put y = 5, 5 = 2x2 + 3 or, x2 = 1 or, x = ∓1 Thus, Domain = { -1, 0, .....
The chemical molecules which carries the hereditary characters from parents to offsprings are genes that are present on "chromosomes". Genes are the functional unit of chromosomes. DNA is the site where this hereditary material is .....
The vacuole in cells have three main functions which are to Provide the plant with support or rigidity, A storage area for nutrients. Waste matter. Can decompose complex .....
Here, tan2θ - ( 1 + √3 )tanθ + √3 = 0 or, tan2θ - 1 - √3tanθ + √3 = 0 or, ( tan2θ - 12 )- √3( tanθ - 1 ) = 0 or, ( tanθ + .....
Check the question .....
Investment during establishment of the factory ( P ) = Rs 40000000 Time ( T ) = 3 years Rate of depreciation ( R ) = 2.5% p.a. Using formula, Price of the factory after 3 years, A = P[ 1 -(R/100)]T = 40000000[ 1 - (2.5/100)]3 = 40000000[ 0.975 ]3 = .....
Here, Cost of the computer (P) = Rs. 50000 Rate of depreciation (R) = 10% Depreciated value (Pt) = Rs. 40500 Time (T) = ? By using the formula, Pt = P(1-D/100)T Solve .....
Given, Initial price of the motorcycle ( P ) = Rs 250000 Time ( T ) = 2 years Price after depreciation ( A ) = Rs 160000 Using formula, A = P[ 1 -( R/100 ) ]T 160000 = 250000[ 1 - ( R/100 ) ]2 160000 / 250000 = [ 1 - ( R/100 ) ]2 0.64 = [ .....
Here, P =Rs.44100 PT = Rs.40000 T= 2 years. R = ? We know. PT = P(1 -R/100)T or, 40000 = 44100( 1 -R/100)2 or, 400/441 = ( 1 -R/100)2 or, (20/21)2 = ( 1-R/100)2 or, 20/21= ( 1 -R/100) or, R/100 = .....
Given, Initial price of the 5 ropani land ( P ) = Rs 280000 Time ( T ) = 3 years Rate of depreciation ( R ) = 5% p.a. Using formula, A = P[ 1 - (R/100)]T = 280000[ 1 - (5/100)]3 = 280000[0.95]3 = 280000 * 0.857375 = Rs 240065 Price of the land .....
Given, Cost of the mobile ( P ) = Rs 6000 Time ( T ) = 2 years Rate of depreciation ( R ) = 30% Using formula, A = P( 1 - R/100 )T = 6000( 1 - 30/100 )2 = 6000( 1 - 0.3 )2 = 6000( 0.7 )2 = 6000 * 0.49 = Rs 2940 Hence, Amount of depreciation = 6000 .....
Given, Rate of depreciation ( R ) = 10% Time ( T ) = 3 years Cost after depreciation ( A ) = Rs 87480 Using formula, A = P( 1 - R/100 )T 87480 = P( 1 - 10/100 )3 87480 = P( 1 - 0.1 )3 87480 = P( 0.9 )3 87480 = P * 0.729 P = 87480 / 0.729 P = Rs .....
Given, Time ( T ) = 2 years Rate of depreciation ( R ) = 10% Price of the machine after depreciation ( A ) = Rs 64800 Using formula, A = P( 1 - R/100 )T 64800 = P( 1 - 10/100 )2 64800 = P( 1 - 0.1 )2 64800 = P( 0.9 )2 64800 = P * 0.81 P = 64800 / .....
Given, Cost of mobile set ( P ) = Rs 25000 Rate of depreciation ( R ) = 5% Time ( T ) = 2 years Using formula, A = P( 1 - R/100 )T = 25000( 1 - 5/100 )2 = 25000( 1 - 0.05 )2 = 25000( 0.95 )2 = 25000 * 0.9025 = Rs 22562.5 Hence, the selling price .....
Given, Cost of cycle (P) = Rs 12000 Rate of depreciation (R) = 10% Time (T) = 2 years Using formula, Depreciated cost of cycle = P( 1 - R/100 )T = 12000( 1 - 10/100 )2 = 12000( 1 - 0.1 )2 = 12000 ( 0.9 )2 = 12000 * 0.81 = Rs 9720 Hence, the cost .....
Given, Cost of computer ( P ) = Rs 40000 Rate of depreciation ( R ) = 10% Time ( T ) = 2 years Using formula, A = P( 1 - R/100 )T = 40000( 1 - 10/100 )2 = 40000( 1 - 0.1 )2 = 40000( 0.9 )2 = 40000 * 0.81 = Rs 32400 Hence, the cost of computer .....
Given, Price of the furniture ( P ) = Rs 16800 Rate of depreciation ( R ) = 15% Time ( T ) = 2 years Using formula, A = P( 1 - R/100 )T = 16800( 1 - 15/100 )2 = 16800( 1 - 0.15 )2 = 16800( 0.85 )2 = 16800 * 0.7225 = Rs 12138 Hence, the cost of .....
Given, Original price ( P ) = x Depriciated price = ( 1/10 ) of x = 0.1x Price after depreciation ( A ) = x - 0.1x = 0.9x Time ( T ) = 1 year Using formula, A = P( 1 - R/100 )T 0.9x = x( 1 - R/100)1 0.9 = 1 - R/100 [ Canceling .....
Given, Original price of the article ( P ) = Rs 1000 Depreciated value = Rs 200 Price after depreciation of the article ( A ) = 1000 - 200 = Rs 800 Time( T ) = 1 year Using formula, A = P( 1 - R/100 )T 800 = 1000( 1 - R/100 )1 800 / 1000 = 1 - .....
Given, Value of the machine before depreciation ( P ) = Rs 3200 Value of the machine after depreciation ( A ) = Rs 3040 Time ( T ) = 1 year Using formula, A = P ( 1 - R/100 )T 3040 = 3200( 1 - R/100 )1 3040 / 3200 = 1 - R/100 0.95 = 1 - R/100 R/100 .....
Given, Cost after depreciation (A) = Rs 72250 Rate of depreciation (R) = 15% Time ( T ) = 1 year Using formula, A = P( 1 - R/100 )T 72250 = P( 1 - 15/100 )1 72250 = P( 1 - 0.15 ) 72250 = P( 0.85 ) P = Rs 85000 Hence, the price was Rs 85000 when it .....
Cost of the typewriter (P)- Rs. 75000 The rate of depreciation (R)- 12.5% Time period (T) = 1 years Pt = P(1 -D/100)T Use this formula to find the .....
Given, Population of the village ( P ) = 24000 Population of the village after 3 years ( PT ) = 27783 Time ( T ) = 3 years [ Between 2061 an 2064 ] Using formula, PT = P[ 1 + (R/100) ]T 27783 = 24000[ 1 + (R/100)]3 27783/24000 = [ 1 .....
The present population of a town (P) = 50000 The rate of a city(R) = 10 % (Birth rate - Death rate) Time (T) = 3 years Population after 3 years (Pt) = ? By using formula, PT = P (1 - D/100)T Solve .....
Here, Initial population = P = 500000 Birth rate = R = 15%. Time = T = 2 years. Now, Population after 2 years = P(1 + .....
Here, Initial population = P = 50000 Final population = PT = 54080. Time = T = ? Rate = R = 4% We know, PT .....
1. had travelled 2. to help 3. so 4. at 5. didn't he? 6. what do you want? 7. an 8. will get 9. are 10. was .....
Here, look at the diagram, Inclination of line = θ = 45o. So, slope = tanθ = tan45o = .....
Here, Initial population of blood doners = P =24000 Final population = PT = 31944. Time = T = ? Rate = R = 1/10 x 100% = 10% We know, P .....
1. the 2. had 3. that 4. call 5. fell 6. feel 7. hadn't I? 8. had been 9. much .....