Students and Teachers Forum
The social organizations focus on the following things: - Empowering marginalize people, women, dalits, backward etc. - Helping people in natural calamities and disasters - To control social problems and evils like dowry system, gambling, .....
Taking L.H.S. = cos28 - sin58 = cos(30 - 2) - sin(60 - 2) = cos30.cos2 + sin30.sin2 .....
Here, Let 10x + y be a two digits number where x and y are the digits in tenth and unit place respectively. now, In first case, 10x + y = 4(x + y ) or, 10x + y = 4x + 4y or, 10x - 4x = 4y - .....
Given, ⋖P + ⋖R = 160 ⋖P = 160 - ⋖R ------------------ [ I ] ⋖Q + ⋖R = 140 ⋖Q = 140 - ⋖R -------------------- [ II ] We know, ⋖P + ⋖Q + ⋖R = 180 [ Sum of angles of a triangle ] 160 - ⋖R + .....
Taking L.H.S. = cos12A + cos4A = 2cos[(12A+4A) ∕ 2].cos[(12A-4A) ∕ 2] .....
Here: tan35°=tan45°-10° Using: =tan45-tan101+tan45.tan10 =1-tan101+1.tan10 [ tan45° = 1 ] =1-sin10cos101+sin10cos10 =cos10-sin10cos10cos10+sin10cos10 =cos10-sin10cos10+sin10 = .....
Let the two digit number be (10x + y). By question, xy = 18 -------------------------- [ I ] (10x + y) - 63 = 10y + x 10x + y - 63 = 10y + x 10x - x = 10y - y + 63 9x = 9y + 63 9x - 9y = 63 9(x - y) = 63 x - y = 7 x = 7 + y .....
Let 'b' cm be the base of the triangle. According to the question, Height (altitude) of the triangle = (b + 3) cm Area of the triangle = 1/2 ⨉ base ⨉ altitude or, 135 = 1/2 ⨉ b ⨉ (b + 3) or, 270 = b2 + .....
Given, Hypotenuse of the right-angled triangle(h) = 13 cm Remaining two sides be 'b' and 'p', By question, b - p = 7 b = p + 7 ---------- [ I ] Using pythagoras theorem, h2 = p2 + b2 132 = p2 + ( p + 7 )2 169 = .....
Let the two sides of the right angled triangle be x and y. By question, x + y = 22 y = 22 - x ------------------ [I] Area of right angled triangle =( 1 ∕ 2 )∗ x ∗ y 60 = ( 1 ∕ 2 )∗ x ∗ y xy = .....
The perimeter of a right angled triangle is 60 cm. Its hypotenuse is 26 cm. Find the other two sides and area of the .....
Let 'W' be the width of path. Length of field (L) = 40 m Breadth (B) = 25 m. We know, area of path outside field = W ( L + B + W) or, 426 = W( 40 + 25 + W) or, 426 = 65W + W2 or, W2 + 65W - 426 = .....
Now, No. of people who like coffee only no(C) = n(C) - n(T ⋂C) .....
Here, Total land = 9/4 ropani So, total selling price of land = 9/4 ⨯ Rs.32,00,000 .....
Electricity is the greatest gift of science to mankind. We have reached a point of our civilization when electricity is used for all purposes. Without it, our existence will be impossible. Electricity is a source of .....
Catch the bus from the station to Kathmandu. You will be informed by the conductor after you reach Kalanki. You will be headed towards new bus park. Get off the bus. Make a phone call after your arrival. Now, catch .....
Wetlands are areas where water covers the soil or is present either at or near the surface of the soil all year or for varying periods of time during the year, including during the growing .....
The supreme court is the highest court of the land. It is also referred to as the court of record. A court of record is a court whose acts and proceedings are recorded safely for perpetual memory and testimony. These records are used with high .....
Here, Let the present age of mother be y and daughter be x. According to 1st condition, xy = 100 or, x = 100/y ..............(i) According to 2nd condition, y + 10 = 2 ( x + 10) or, y + 10 = 2x + 20 or, y + 10 = .....
Let the number be a The square of the number be a2 The sum of the number is 56. ∴ a2 + a = 56 We now solve the equation: or, a2 + a = 56 or, a2 + (8-7)a - 56 = 0 or, a2 + 8a - 7a - 56 = 0 or, a(a + 8) - .....
Let the consecutive even numbers are y and y + 1 According to question, y ( y +1 ) = 240 or, y2 + y - 240 = 0 or, y2 + 16y -15 y - 240 = 0 or, y ( y + 16 ) - 15 ( y + 16) = 0 or, ( y - 15) ( y + 16) = 0 Either, y - .....
Here, In right angled triangle BEC, CE = √[BC2 - BE2] = √[132 - 122] = 5cm Now, Area of trap.ABCD = 1/2 ⨯ .....
Here, PT = PQ - TQ = 17cm - 7cm = 10cm In right angled triangle PTS, ST = √[SP2 - PT2] = √[262 - 102] = 24cm. Now, Area of trap.PQRS = .....
LHS = ( cosecθ + cotθ) / ( cosecθ - cotθ) = ( cosecθ + cotθ) ( cosecθ + cotθ) / [( cosecθ - cotθ)( cosecθ + cotθ) ] = ( cosecθ + cotθ)2 / ( .....
3. Here, LHS = (tanθ - cotθ) / sinθcosθ = [ sinθ/cosθ - cosθ/sinθ] / sinθcosθ [ Since, tan = sin/cos & cot = cos/sin] .....
Here, ∡BAD = 90o, [ Since, angle in semi-circle.] ∡BAC = ∡BAD - ∡ CAD = 90o - 26o = 64o Finally, x = ∡ BAC [ Angle in alternate segment.] Can you write the .....
Here, ∡ P + ∡ R = 180o [ Opposite angles od cyclic qd. are supplementary.] Or, ∡R = 180o - 110o Again, x = ∡R .....