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180p = 100p + 80p          = Re. 1 and .....

Given, Two angles of triangle are; 800 and 700. Let x be the third angle. Then, x + 800 + 700 = 1800 (∵ The sum of interior angles of a triangle) or, x + 1500 = 1800 or, x = 1800 – 1500 ∴ x = 300 Hence, the size of third angle is .....

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According to National number system = 27, 56, 790 According to International number system = 2, 756, .....

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Four million two hundred sixty one thousand five hundred and twenty .....

nem ------------- men  dwoo ------------ wood arcd -------------- card  yot --------------- toy  gnos ------------- .....

According to National number system = 7, 92, 64, 950 According to International number system = 79, 264, .....

Given, Angles of a quadrilateral are;  a + 100,  a + 200,  a + 300 a =? Then, a + 100 + a + 200 + a + 300 + a = 3600 (∵ The sum of interior angles of a quadrilateral) or, 4a + 600 = 3600 or, 4a = 3600 – 600 or, 4a = 3000 or, a .....

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फ्याउरो, .....

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Given number is, २३४१२६५७८ Writing in Devanagari system, = तेईस करोड एकचालीस लाख छब्बिस हजार पाँच सय अठहत्तर  Writing the number name in .....

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65 p = 65100 rupees         = Rs. .....

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त्रिहत्तर लाख असी हजार दुइ सय .....

Given area of Nepal is, 141181 sq. km Writing the area in Hindu-Arabic system of numeration, 1, 41, 181 = One lakh forty one thousand one hundred eighty one. Writing in International system of numeration, 141, 181 = One hundred forty one .....

An ox An eagle An .....

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Given seven digits: 5, 3, 8, 1, 9, 6, 4 The greatest number   = 9865431 The least number        = 1345689 Now, their sum is given by; = 9865431 + 1345689 = .....

Face value = 9 Place value = .....

Face value = 5 Place value = .....

Face value = 6 Place value = .....

Supplement of 1250 = 1800 – 1250   (∵ sum of supplementary angles is 1800 )                                       = .....

425 p = 425100 rupees           = Rs. .....

= 40000000 + 5000000 + 6000 + 70 + .....

165p = 100p + 65p          = Re. 1 and .....

Rs. 30 = 30 × 100 p            = 3000 .....

= 300000000 + 500000 + 90000 + 8000 + 600 + 40 + .....

Given,  n(S)= 6×6=36 Let E be the event of getting same number on both the faces. Then, E= {(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}     ∴ Probability of getting same number on both the faces is, P(E)= nEnS   .....

Rupees        Paisa    24               16 + 36               34     60              .....

= .....

600 p = 600100 rupees           = Rs. .....

Rs. 5 = 5 × 100 p          = 500 .....

a.  Given,      S= {1,2,3….20} ∴ n(S)= 20 Let E be the event of square numbered cards. E={1,4,9,16} ∴ n(E)=4 The probability of getting a square numbered card is, P(E) = nEnS         .....

Three hundred fifty one rupees and thirty three paisa = Rs. .....

= .....

Fifteen rupees and ten .....

Six rupees and six paisa = Rs. .....

One hundred fifty four rupees and seventy paisa = Rs. .....

When three coins are tossed at a time. The sample space will be     S={(H,H,H),(H,H,T),(H,T,H),(T,H,H),(T,H,T),(T,T,H),(H,T,T),(T,T,T)}     n(S)= 8. a.    Let E1  be the event of getting one head and two .....

Rs. 15 = 15 × 100 p            = 1500 .....