∠PQR = .....

2 crore = 20000000 Writing 2 crore in International system putting commas,  20000000 = 20,000,000 ∴ There are 20 million in 2 .....

= .....

Smallest number = 12345689 Greatest number = .....

Solution: ∠MNO = .....

Seventy six rupees and twenty eight paisa = Rs. .....

Solution: ∠ABC = .....

Forty seven rupees and three paisa = Rs. .....

One hundred and nine rupees and five .....

Twenty five rupees and forty five .....

Solution: ∠ XOY = .....

= 798, 465, 804 = Seven hundred ninety eight million four hundred sixty five thousand eight hundred and .....

= 37, 892, 006, 542 = Thirty seven billion eight hundred ninety two million six thousand five hundred and forty .....

esro ------ rose archi ----- chair dlich ----- child scals ----- class  geg  ------ .....

Here, For the length of the PQ of Quadrilateral PQRS,         P = (5, -4) = (x1, y1)        Q = (1, -1) = (x2, y2)        PQ = √( (x2-x1)2+ (y2-y1)2 )       .....

Let,      (x1,y1) = P(x,3)      (x2,y2) = Q(7, -1).      PQ = 5 units. Using distance formula,        Distance = √[(x2 - x1)2+(y2-y1)2] or, 5 = √[(x-7)2 + ( .....

Fifty four rupees and seventy five .....

125 = 5 × 5 × 5          = 53 ∴ ∛ 125 = ∛ (53)                   = .....

Here, 15 flowers are planted in each row and column of a square. So, the required number of flowers is square of 15.  ∴ Required flower = 152                           .....

5230 p = 5230100 rupees             = Rs. .....

Cube of 90 = 903                     = 90 × 90× 90                    = .....

= 2, 34, 56, 287 = Two crores thirty-four lakh fifty-six thousand two hundred and .....

We have given,      p, b and h are the sides of a right angled triangle. Using Pythagoras theorem,  h2= p2 + b2                                 .....

= 30, 02, 00, 083 = Thirty crore two lakh eighty .....

1.    Ahilya 2.    Draupadi 3.    Kunti 4.    Tara 5.   .....

.....

Cube of 12 = 123                     = 12 × 12 × 12                    = .....

Cube of 24 = 243                     = 24 × 24 × 24                    = .....

Krodh     -----------  Anger Lobh       -----------  Greed Moha      -----------  Love Ahankar  -----------  Arrogance Matsarya -----------  .....

Square of 40 = 402                       = 40 × 40                      = .....

बहिनी कविता पढ्छे .....

= 43, 891, 658, 428 = Forty three billion eight hundred ninety one million six hundred fifty eight thousand four hundred twenty .....

Square of 150 = 1502                         = 150 × 150                        = .....

To find the H.C.F. of 20 and 27, ∴ H.C.F. = 0 There are no any common factors of 20 and 27.  These numbers are therefore called as co-prime .....

The integers in between -5 to 10 are; -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, .....

So, 845 is rounded down to 800. Reason:(In the given number 845, the number formed by last two digits is 45 which is lesser than 50. So, the next number lesser than 845 and ending with two zero is .....

= 6, 01, 53, 27, 98, 045 = Six kharab one arab fifty three crore twenty seven lakh ninety eight thousand forty .....

= 56, 88, 44, 642 = Fifty six crore eighty eight lakh forty four thousand six hundred and forty .....

To find the L.C.M of 16, 32 and 48 ∴ L.C.M. = 2 × 2 × 2 × 2 × 2 × 3                 = 96 So, the required smallest number is .....

∴ L.C.M. = common factors × remaining factors                 = 2 × 2 × 2 × 3 × 2                 = .....

                    .....

So, 158 is rounded up to 200. Reason:(In the given number 158, the number formed by last two digits is 58 which is greater than 50. So, the next number biggert than 158 and ending with two zero is .....

10, 00, 79, .....

क) बहिनी कक्षा एकमा पढ्छ । (बेठिक) ख) उनीहरू घर गए । (ठिक) ग) तिमीहरू कथा पढ्छ । (बेठिक) घ) .....

∴ L.C.M. = common factors × remaining factors                 = 2 × 5 × 3 × 2 × 2                 = .....

    3 more than -4 = -4 + 3 = - .....

    10 less than - 8 = - 8 - 10 = - .....

   7 more than 0  = 0 + 7  = .....

75, 52, 19, .....

Cube of 8 = 83                   = 8 × 8 × 8                  = .....