Here, We have to add cube of a number to twenty seven but the number is not given. So, let us suppose the number to be x.  Let the number be x.  Now, let us find the cube of the number x.  Cube of x = x3. Since, we have to add cube of .....

The function of chromosome is to transmit the genetic characters from parents to their .....

0.6 = .....

5876 .....

Solution: Here, We have to add the polynomials 2x2 - 1/2x, 1/2x + 2 and 1- 2x2 by performing horizontal addition. So, let us write the given expression with the plus sign in between them.                  .....

   90 + [11 × {17 - (8 ÷ 2)}] = 90 + [11 × {17 - 4}] = 90 + [11 × 13] = 90 + 143 = .....

Solution: Here, we have to classify the polynomial 3x3 - 3x2y + 3xy2 - y3 according to its number of terms.  As we know,  (i) Monomial is a polynomial having only one term.  (ii) Binomial is a polynomial having 2 terms.  (iii) .....

Solution: Here, we have to find the value of m in the polynomial 4xm y2m z3m.  In order to find the value of m, we need to sum the power of the variables of the algebraic expression.  So, let us sum the power of variables in .....

Here, the two complementary angles are in ratio 4:5. Let, 4x° and 5x° be two angles. Then, 4x° + 5x° = 90° [Being complementary angles] or, 9x° = 90° or, x° = 90°9 ∴ x° = 10° Now, 4x° = 4 .....

Solution: Here, We have to find the degree of the polynomial 2x + 4x3 + 2x2 - 5. In order to find the degree of the polynomial, we need to find the power of the variable of the algebraic expression. The highest power of an algebraic term will .....

As we know that power is the rate of doing work with time. The unit of power is a watt or J/s. So, if a power of an electric engine is 60 watt, it indicates that that electric engine consumes 60 Joule energy in 1 second to perform .....

Solution: Here, we have to classify the polynomial 5x2y + 2xy + 5y4y according to its degree.  As we know,                     Linear polynomial is a polynomial of degree 1.     .....

The energy possessed by the blowing air is known as wind .....

Solution: Here, We have to find the numerical coefficient of the term -(√3)/2 abc.  As we know, a coefficient is any one of the factor of an algebraic term with the sign of the term, the factors of given algebraic expression are .....

Here, We have to add product of m and n by 2. So, let us multiply m and n first.  The product of m and n = mn. Since, we have to add two to the product of m and n. Let us add 2 and mn.  Therefore, the required algebraic expression is 2 + .....

जाऊ          जाऊँ दिऊँ            देउ औँलो         औलो जुगा          .....

Here we have to find the value of quadratic polynomial 36x2+60xy+25y2  when x= 4 and y= -7, so let us write the expression first.         = 36x2+60xy+25y2 Here we have also been given the value of x and y as x= 4 and y= .....

Solution, Here we have to find the value of quadratic polynomial 49x2+126xy+81y2  when x= 4 and y= 7, so let us write the expression first.         = 49x2+126xy+81y2 Here we have also been given the value of x and y as x= .....

Solution, Here we have to simplify the expression x/2x(3x - 5y) × (5xy(3x - 5y))/10xy × 8x/6y                                         .....

Solution, Here we have to express x2 y2+ 2 + 1/(x2 y2 )as a perfect square. Here, x2 y2+ 2 + 1/(x2 y2 ) To express x2 y2+ 2 + 1/(x2 y2 ) as a perfect square let us represent the given trinomial expression into a2+ 2ab + b2 and use in the formula .....

Solution, Here we have to simplify the expression 3(x + y) – 2(3x – y)                                               .....

Here, we have to find the value of quadratic polynomial (x + 1/x)2=20 if the linear polynomial x - 1/x = 4 and quadratic polynomial x2 + 1/x2  = 18. Given, x - 1/x = 4 and x2 + 1/x2 = 18. To prove, (x + 1/x)2 = 20 let us .....

Deuterium is an isotope of hydrogen with atomic mass .....

Solution, Here we have to simplify the binomial expression (x + y)/(x -y) - (x + y)/(x - y) = (x + y)/(x - y) - (x + y)/(x - y) For the simplification of this expression, we can first take LCM of the denominator  = (x + y – (x + y))/(x - .....

Solution, Here we have to simplify the binomial expression 3/xy-(3 - x3 y3)/xy = 3/xy-(3 - x3 y3)/xy For the simplification of this expression, we can first take LCM of the denominator  = (3 –( 3- x3 y3))/xy Now, let us open the brackets .....

Here, we have been asked to find the number of certain percentage.  At first let us write down given information: We have, 90% of 40 This can also be written as,  = 40 × 90%  Let us remove % symbol by dividing by 100. = 40 .....

Here, we have been given a value and we have been asked to find the percentage. At first let us write down given information: We have,  9 out of 10 Now let us find the required percentage.  So, we can write,  9 out of 10,  First .....

The three example of the festivals are: i)    Dashain  ii)   Teej  iii)  .....

Here, we have a ratio 115 to 60. We have been asked to find the ratio. At first let us write down given information: Given, 115 to 60 Let us write it on fraction,  = 115/60  Let us multiply both factors by their common factor i.e 5, = .....

Here, we have been given the total number of teacher and there are 25 female teachers. We have been asked to find the ratio of male teachers to female teachers. At first let us write down given information: We have,  Total teacher = 60 Female = .....

Here, we have been given the ratio of speed of train and car. We have been asked to find the speed of train where speed of car is given. At first let us write down given information: We have,  Train to car = 5:3 Speed of car = 60 km/hr Speed of .....

Here, we have been given the series of number. We have been asked to find the value of first proportional. At first let us write down given information: Given,  9, 5, 15 Let first proportional be x.  So, series will be x, 9, 5, .....

Here, we have been given a percentage. We have been asked to express the percentage into decimal. At first let us write down given information: Given,  65% To convert percentage to decimal, we should put 100 in denominator and perform division .....

Here, we have been asked to find the number of certain percentage.  At first let us write down given information: We have, 33.33% of 90 students  This can also be written as,  = 90 students × 33.33%  Let us remove % symbol .....

Solution : Cube of 2 = 23                  = 2 × 2 × 2                  = 8 ∴ Cube of 2 = .....

Here, we have been asked to find the number of certain percentage.  At first let us write down given information: We have, 75% of Rs. 250 This can also be written as,  = Rs. 250 × 75%  Let us remove % symbol by dividing by .....

Here, we have a ratio 16 kg:24 kg. We have been asked to express it in the simplest form. At first let us write down given information: Given, 16 kg:24 kg Let us write it on fraction,  = (16 kg)/(24 kg)  Let us multiply both factors by .....

Here, we have been given the proportion. We have been asked to find the value of x. At first let us write down given information: Given,  2 : 3 = 4 : x So, we can write 2/3 = 4/x Let us perform cross-multiplication operation, 2x = 12 Let us .....

Here, we have been given the ratio of two squares. We have been asked to find the value of length of second square where length of first square is given. At first let us write down given information: We have,  Ratio of length of two square = .....

Here, we have been given a percentage. We have been asked to express the percentage into decimal. At first let us write down given information: Given,  35% To convert percentage to decimal, we should put 100 in denominator and perform division .....

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Solution, Here we have to divide the term 8x4 y4  by the term 4x4 y       Or, 8x4 y4 ÷ 4x4 y This horizontal division can be written in the vertical term as      Or,   (8x4 y4)/(4x4 y) Now, let us .....

Here, we have been given the series of numbers. We have been asked to find that whether they are in proportion or not. At first let us write down given information: Given,  2, 4, 6, 12 To be proportion, the ratio of first two numbers should be .....

Here, we have been given as percent figure. We have been asked to express in fraction in simplest form and as a decimal. At first let us write down given information: Given,  18% To express percentage as fraction, we should divides percentage .....

Here, we have a ratio 60 cm3 : 125cm3. We have been asked to express it in the simplest form. At first let us write down given information: Given, 60cm3 : 125cm3 Let us write it on fraction,  = (60cm3)/(125cm3 )   Let us multiply .....

Here, we have a ratio 25:75. We have been asked to reduce it in their lowest terms. At first let us write down given information: Given, 25:75 Let us write it on fraction,  = 25/75  Let us multiply both factors by their common factor i.e .....

Here, we have been given as percent figure. We have been asked to express in fraction in simplest form and as a decimal. At first let us write down given information: Given,  0.8% To express percentage as fraction, we should divides percentage .....

Here, we have a ratio 625:375. We have been asked to reduce it in their lowest terms. At first let us write down given information: Given, 625:375 Let us write it on fraction,  = 625/375  Let us multiply both factors by their common factor .....

Here, we have been given the ratio of pupils and their hand. We have been asked to find the number of pupil where their hand is given. At first let us write down given information: We have, Pupils to hand = 1:2 Number of hands = 64 Number of pupils .....