Here, we have a ratio 2 years to 9 months. We have been asked to express it in the simplest form. At first let us write down given information: Given, 2 years to 9 months We can also write,  24 months to 9 months Let us write it on .....

Here, we have been asked to find the number of certain percentage.  At first let us write down given information: We have, 30% of 150 This can also be written as,  = 150 × 30%  Let us remove % symbol by dividing by 100. = 150 .....

Here, we have been given the series of number. We have been asked to find the value of third proportional. At first let us write down given information: Given,  10, 2, 10 Let third proportional be x.  So, series will be 10, 2, x, .....

The animals having the characters of the organisms of lower group and higher group are called bridge .....

Here, we have been given total number of student and number of girls. We have been asked to find the percentage of girls and boys. At first let us write down given information: We have,  Total student = 36 student, Girls = 16 Boys = 36 - 16 = .....

Here, we have been given two ratios. We have been asked to find whether they are in proportion or not. At first let us write down given information: Given,  2:5 and 9:21 To be in proportion the ratio of first two numbers should be equal to .....

Here, we have been given the value of mixture of milk and water. We have been asked to find the ratio of milk and water. At first let us write down given information. We have,  Total mixture = 30 litres Water = 12 litres Milk = 30 - 12 .....

A nuclear reaction that takes place at very high temperature is called thermonuclear .....

Here, we have been given the percentage of people of a village who are illiterate. We have been asked to find the number of illiterate people in village. At first let us write down given information: In a village,   Percentage of illiterate = .....

Here we have been given the values. We have been asked to find the value at 100%. At first let us write down given information: We have,  150% is 15 l  Let the value at 100% be x. Now, we can say 15 l is 150% of x. So, we can .....

Here, we have been given a percentage. We have been asked to express into lower term of fraction. At first let us write down given information: Given,  25%  To express percentage in fraction, we should divide percentage by 100 and remove % .....

Here, we have been given a percentage. We have been asked to express into lower term of fraction. At first let us write down given information: Given,  30%  To express percentage in fraction, we should divide percentage by 100 and remove % .....

Solution: Let the fourth proportional of 5, 7and 15 is x. Then, 5: 7 = 15 : x Or, 57 = 15x Or, 5x = 15 × 7 Or, 5x = 105 Or, x = 1055 ∴ x = 21 ∴ The fourth proportional of 5, 7and 15 is .....

Here, we have been given as percent figure. We have been asked to express in fraction in simplest form and as a decimal. At first let us write down given information: Given,  42% To express percentage as fraction, we should divides percentage .....

Solution: Here, 4 : 20 = 9 : y 420 = 9y Or, 4y = 9×20 Or, y = 9×204 Or, y = 9 ×5 ∴ y = .....

Solution: Area of the base of a cube = 256 cm2     Since base area of a cube = l2,     l2 = 256 cm2 Or, l = √ 256 = 16 ∴ Length of the cube = 16 cm     Now,  Total surface area of the .....

Solution: Area of the base of a cube = 64 cm22     Since base area of a cube = l2,     l2 = 64 cm2 Or, l = √ 64 = 8 ∴ Length of the cube = 8 cm     Now,  Total surface area of the cube = .....

Here, we have been given that the number of student has increased. We have been asked to find the percentage of increased number of a student. At first let us write down given information: In a school, Last year student = 250 This year student = .....

Here, we have been given the number of children in a town. We have been asked to find the percentage of children. At first let us write down given information: In a town,  Children = 1/10 Percent of children =? Now, let us find the percentage .....

Here, we have been given as percent figure. We have been asked to express in fraction in simplest form and as a decimal. At first let us write down given information: Given,  65% To express percentage as fraction, we should divides percentage .....

Here, we have been given a percentage. We have been asked to express into lower term of fraction. At first let us write down given information: Given,  28%  To express percentage in fraction, we should divide percentage by 100 and remove % .....

Here, we have been given as percent figure. We have been asked to express in fraction in simplest form and as a decimal. At first let us write down given information: Given,  12.5% To express percentage as fraction, we should divides percentage .....

Solution: Let N and E be the set of students who speak Nepali and English respectively. no(N) = 22     no(E) = 12    n(N∪E) = 45    n(N∩E) = ? We have,             .....

Solution: The scale 1: 500 ∴ 500 cm = 500/100 = 5 m Now, 1 cm represents 5 m. ∴ 2.5 cm represents = 25 ×5 m=12.5 m ∴ The actual distance between the two places is .....

Here, we have been given a percentage. We have been asked to express into lower term of fraction. At first let us write down given information: Given,  35%  To express percentage in fraction, we should divide percentage by 100 and remove % .....

Solution: Here, 4 : 5 = y : 35 45 = y35 Or, 5y = 35×4 Or, y = 35×45 Or, y = 7 × 4 ∴ y = .....

Solution: Length of the cartoon (l1) = 8 m Breadth of the cartoon (b1) = 6 m Height of the cartoon (h1) = 4 m Volume of the cartoon (V1)     = l1b1h1                    .....

Solution: Here,  Amount of water that the cubical tank can hold = 343000 l         = 343000/1000 m3         = 343 m3 ∴ Volume of the cubical tank = 343 m3  Since, volume of a cube = .....

Solution: Length of the match box (l) = 4 cm Height of the match box (h) = 2.5 cm Volume of the match box (V) = 40 cm3 Breadth of the match box (b) = ? We know,  Breadth of the match box (b)     = V / lh    .....

Solution: Length of the cuboid (l) = 28 cm Breadth of the cuboid (b)= 10 cm     Height of the cuboid (h) = 8 cm We know,  Total surface area of cuboid (T.S.A) = 2 (lb + lh + bh)            .....

Here the four angles of a quadrilateral are, a, 2a, 3a, and 4a. ∴ a + 2a + 3a + 4a = 360° (Sum of interior angles of a quadrilateral is 360o. ) or, 10a = 360° or, a = 360°10         = 36° ∴ The .....

Solution: Length of the cuboidal box (l) = 15 cm Breadth of the cuboidal box (h) = 12 cm Total surface area (TSA) = 846 cm2 Breadth of cuboidal box (b) = ? We know,  Total surface area of cuboidal box (TSA) = 2 (lb + bh + lh) or, 2 (15 X 12 + .....

Given,  Cost price = CP = Rs.740 Selling price = SP = Rs.700 Here, CP > SP So,  Loss = CP - SP         = Rs.740 -  Rs.700         = Rs.40 Finally , Loss  % =LossCP×100%  .....

Here, The ratio of angles of a triangle is 2:3:4. Let the measure of the angles of triangle be 2x°,3x° and 4x°. 2x° + 3x° + 4x° = 180o [∵The sum of angles of a triangle = 180o] or, 9x° = 180°  or, x = .....

Here,                x2 +y2-ax-by-12=0  or,  x2 -2.x.a/2  +(a/2) 2 + y2 -2.y.b/2 +(b/2)2 = 12+(a/2)2 + (b/2)2  or,  (x-a/2)2  +   (y-b/2)2  =  (a/2)2 + (b/2)2 .....

Let, hypotenuse (h) = 10 cm Then, h2 = 102 = 100 cm2 base (b) = 5√3  cm Then, b2 = (5√3)2 = 75 cm2  perpendicular (p) = 5 cm Then, p2 = 52 = 25 cm2  Now, p2 + b2 = 25 cm2 + 75 cm2 = 100 cm2 Therefore, p2 + b2 = h2 Since .....

The darkening of a heavenly body when it passes through the shadow of another heavenly body is called .....

Here, we have been given the percentage of iron and copper in an alloy. We have been asked the amount of copper in 50 kg of the alloy. At first let us write down given information: In an alloy, Iron = 55% Copper = 100% - 55% Let us perform .....

Here, we have been given two angles. We have been asked to find whether given pair of angles is complementary or supplementary. First let us write down given information: Given, 110° and 70° To find the pair of angles are whether .....

Universe is the vast surrounding space which consists of planets, stars, galaxies, constellations, satellites, asteroids, comets, .....

.....

Given, Cost price = CP = Rs.804 Selling price = SP = Rs.1004 Here, SP > CP So,  Gain = SP - CP          = Rs. 1004 - Rs. 804          = Rs.200 Finally , Gain % = GainCP .....

                                                                      .....

Areolar tissues are the tissues which are either very loosely held together or densely packed with fibres found under the skin between muscles and around the blood .....

1. Did you use to live in Old Baneshwor? 2. He didn't use to enjoy cycling, but he does now. 3.I know it sounds funny now, but we didn't use to grow vegetables. 4. We used to live in New York when I was a kid. 5. There didn’t use to be .....

Solution, Here we have been asked to find the product of three algebraic expressions (x + 2) (x – 2) and (x2+4) We know, A continued product is the product of three or more factors. Given (x + 2) (x – 2) (x2+4) Here we have to find the .....

The animals that live in the forest are known as jungle .....

The pressure exerted by the weight of the air present in the atmosphere is called atmospheric .....

Solution, Here, we have to find the value of quadratic polynomial p2+1/p2  And we have been given the value of linear polynomial p-1/p Given, p-1/p=4 So, let us square on both side so thst the linear polynomial p-1/p changes to quadratic .....

Here, we have to find the value of cubic polynomial a3+b3 And we have been given the value of linear polynomial a + b and quadratic polynomial ab. Given, a + b = 3   ab = 2 We also know the formula for a3+b3 is (a+b)3-3ab(a+b). We know,   .....