Students and Teachers Forum
Given, Diameter of the cylinder (d) = 14 cm or, radius of the cylinder (r) = d2 = 7 cm Curved surface area of the cylinder (CSA) = 1320 cm2 .....
Let r be the radius & h be the height of cylinder. Given, Circumference of base of cylindrical drum (C) = 88 cm Or, 2πr = 88 cm Or, 2⨉ 3.14 ⨉ r = 88 .....
Given, Diameter of the solid cylinder (d) = 7 cm Radius of the cylinder (r) = d/2 = 7 cm/2 = 3.5 cm Length of the solid .....
Given, Diameter of the base of the cylinder (d) = 42 cm Radius of the base of the cylinder (r) = 21 cm Height of the cylinder (h) = 30 cm. We know, (i) Area of .....
Given, Circumference of the base (C) = 88 cm Or, 2πr = 88 cm where, r = radius of cylinder. Or, 2 ⨉3.14 ⨉ r = 88 cm Or, 6.28 .....
Given, Volume of the sphere (V) = 7241.14 cm3 Let r be the radius of sphere. We know, Volume of sphere (V) = 4/3 πr3 Or, 7241.14 .....
Given, Diameter of the solid cylinder (d) = 14 cm Radius of the cylinder (r) = 7 cm Length of the .....
Given, Radius of cylinder (r) = 4.2cm Height (h) = 4.9cm Total srface area (TSA) = ? We know, T.S.A of cylinder = 2πr(r+h) .....
Given, Diameter of the cylinder (d) = 7 m Radius of the cylinder (r) = 3.5 m Depth of the cylinder (h) = 20 m. Now, Inner surface area including base (A) = .....
Given, Height of cylinder = h = 15cm Area of the base of the cylinder (A) = 616 cm2 Or, πr2 = 616 cm2, where r is radius of cylinder. Or, 3.14 ⨉ r2 .....
Given, Radius of the base of the cylinder (r) = 7 cm Height of the cylinder (h) = 14 cm. We know, (i) Area of the curved surface of cylinder (CSA) = 2πrh .....
Given, Length of the capsule (H) = 14 mm Diameter of the capsule (d) = 5 mm Radius of the capsule (r) = d2 .....
Given, Length of the iron pipe (h) = 280 cm Internal diameter of the iron pipe (d2) = 10 cm Internal radius of the iron pipe (r2) = 5 cm .....
Given, Measure of side of the cube (l) = 50 cm We know, Total surface area of the cube (TSAcube) = 6l2 .....
Let r be the radius and h be the height. Given, Area of the base of cylinder (A) = 7546 cm2 Or, πr2 = 7456 cm2 Or, 3.14 ⨉ r2 = 7456 cm2 Or, r2 .....
Given, Diameter of the cylindrical vessel (d) = 1.4 m Radius of the cylindrical vessel (r) = d 2 = 0.7 m Capacity of the cylindrical vessel (V) = 770 .....
Given, Volume of the cylindrical can (V) = 1232 cm3 Height of the cylindrical can (h) = 8 cm. We know, Volume of a cylinder (V) = πr2h Or, 1232 cm3 = 3.14 .....
Given, Edge of the cube (l) = 22 cm Height of the cylinder (h) = 11 cm. According to the question, Area of curved surface of cylinder (CSA) = Total surface area of .....
Here, Diameter of the cylinder (d) = 3.5 m So , radius of the cylinder (r) = d2 = 1.75 m Capacity of the vessel (V) = 770 .....
Given, Area of great circle(A) = πr2= 5cm2. CSA of hemi-sphere = ? We have, CSA of hemisphere= 2πr2 .....
Here, Volume (V) = 1.54 liter=1.54 1000 cm3 = 1540 cm3 And, area of base(A) = 77 cm2 We have, Volume = Area of base ⨉ height Or, height = .....
Given, Volume of the solid object (V) = 616 cm3 Height of the solid object (h) = 8 cm We know, Volume of the half of cylinder (V) = 12πr2h Or, 616 cm3 = 2214 r2 ⨉ 8cm Or, r2 = 49 cm2 Or, r = √(49cm2 ) Or, r = 7 .....
Given, Height of the cylinder (h) = 1.45 m = 1.45 ⨉ 100 cm .....
Given, External radius of the spherical ball (R) = 9 cm Volume of the ball (V) = 2531.05 cm3. We know, Volume of the hollow sphere (V) = 43 π(R3 – r3) Or, .....
Here, Radius and slant height of the cone are r and l respectively. The total surface area of a cone is given by, TSA = curved surface area + area of circular .....
Given, Diameter of the base of cylinder (d) = 70 cm Radius of the base of cylinder (r) = d2 = 35 cm Height of the cylinder (h) = 1 m = 100 cm. We know, Total .....
Given, Circumference of the base (C) = 132 cm Or, 2πr = 132 cm Or, 2 ⨉ 3.14 ⨉ r = 132 cm Or, 6.28 ⨉ r .....
Given, Radius of the sphere (r) = 14 cm We know, Surface area of the sphere (TSA) = 4πr2 .....
Given, Diameter = d = 10.5cm Height = h = 15.57cm Curved surface area = ? We have, CSA of cylinder = 2πrh = πdh .....
Given, Height of the cylinder (h) = 12 cm Circumference of the base of cylinder (C) = 88 cm Or, 2πr = 88 cm, .....
Here, we have given, Circumference of the base (C) = 2πr = 88cm Sum of radius and height (r+h) = 24cm. TSA of cylinder = ? Now, Total .....
Given, Total number of circular plates (N) = 35 Thickness of each plate (t) = 1 cm So, the height of the cylinder so formed (h) .....
Given, Height of the cylinder (h) = 10 cm Volume of the cylinder (V) = 3.85 cm3 We know, Volume of the cylinder (V) = πr2h Or, 3.85 cm3 .....
Here, Let r be the radius of hemi-sphere. Volume of the hemisphere (V) = 134.09 cm3 We know, Volume of the hemisphere (V) .....
Given, Volume of the hemisphere (V) = 50.307 cm3 Let r be the radius of hemi-sphere. We know, Volume of the hemisphere (V) = .....
Given, Area of the base of the hemisphere (A) = 452.57 cm2. Let r be the radius of hemi-sphere. We know, Area of base of a hemisphere (A) = .....
Given, Height of the cylinder (h) = 16 cm Curved surface area of cylinder (CSA) = 176 cm2 Or, 2πr ⨉ h = 176 cm2 Or, 2πr ⨉ 16 cm = 176 .....
Here, Height = h = 7cm The total surface area of the cylinder = TSA = 1884 7 cm2 . Let r be the radius of base. Then, TSA = 2πr2+2πrh Or, 18847 .....
Given, Circumference of the great circle of the hemisphere (A) = 44 cm Or, 2πr = 44 cm where, r is .....
Here, Radius of cone (r) = 12 cm2= 6 cm Slant height (l) = 10 cm So, Height of cone (h) = √[l2 - r2] .....
Let x be any constant. Since the height of the cone and cylinder are in the ratio 2:3, Height of cone = 2x Height of the cylinder = 3x According to the question, 2x + 3x = 30 Or, x = 6 cm So, Height of cone = 2x = 2 X 6 .....
Given, Total surface area of hemisphere (TSA) = 11550 cm2. Let r be the radius of hemi-sphere. We know, Total surface area of hemisphere (TSA) = 3πr2 .....
Given, Diameter (d) = 14cm. Surface area = ? We have, Surface area of sphere = πd2 .....
Given, Volume of the hemisphere (V) = 4603.23 cm3 We know, Volume of the hemisphere (V) = 23 πr3 Or, 4603.23 cm3 =23 ⨉ 227 ⨉ r3 Or, 4603.23 cm3 = .....
Given, Radius of the base (r) = 14 cm Height of the cylinder (h) = 20 cm We know, (i) Area of the curved surface of cylinder (CSA) = 2πrh .....
Given, Volume of the hemisphere (V) = 8316 cm3 We know, Volume of the hemisphere (V) = 27 πr3 , r is radius of sphere. Or, 8316 cm3 = 23 ⨉ 227 ⨉ .....
Let r be the radius of sphere. Given, Total surface area of the sphere (TSA) = 201.14 cm2 Or, 4πr2 = 201.14 cm2 or, πr2 = 50.285cm2. Again, Total .....
Given, Length of the pipe (h) = 12 cm Outer radius of the pipe (r1) = 2 cm. Inner radius of the pipe (r2) = 1 cm. We know, Total surface area of the .....
Let r be the radius of sphere. Given, Volume of the sphere (V) = 33.52 cm3 We know, Volume of sphere (V) = 43 πr3 Or, 33.52 cm3 = 43 ⨉ 227 ⨉ r3 Or, 33.52 cm3 = 8821 ⨉ r3 Or, 33.52 cm3 ⨉ .....
Given, Radius of 1st sphere (r1) = 1 cm So, volume of 1st sphere (V1) = 43 πr13 .....