Students and Teachers Forum

Given,        Diameter of the cylinder (d) = 14 cm        or, radius of the cylinder (r) = d2 = 7 cm        Curved surface area of the cylinder (CSA) = 1320 cm2       .....

Let r be the radius & h be the height of cylinder. Given,         Circumference of base of cylindrical drum (C) = 88 cm         Or, 2πr = 88 cm         Or, 2⨉ 3.14 ⨉ r = 88 .....

Given,        Diameter of the solid cylinder (d)     = 7 cm        Radius of the cylinder (r)     = d/2 = 7 cm/2 = 3.5 cm         Length of the solid .....

Given,        Diameter of the base of the cylinder (d) = 42 cm        Radius of the base of the cylinder (r)  = 21 cm        Height of the cylinder (h) = 30 cm. We know, (i) Area of .....

Given,       Circumference of the base (C) = 88 cm Or, 2πr                 = 88 cm         where, r = radius of cylinder. Or, 2 ⨉3.14 ⨉ r  = 88 cm Or, 6.28 .....

Given,         Volume of the sphere (V) = 7241.14 cm3          Let r be the radius of sphere. We know,        Volume of sphere (V)      = 4/3 πr3 Or,  7241.14 .....

Given,           Diameter of the solid cylinder (d)     = 14 cm           Radius of the cylinder (r)      = 7 cm            Length of the .....

Given,        Radius of cylinder (r)  = 4.2cm        Height (h) = 4.9cm        Total srface area (TSA) = ? We know,        T.S.A of cylinder = 2πr(r+h)   .....

Given,         Diameter of the cylinder (d) = 7 m         Radius of the cylinder (r)  = 3.5 m         Depth of the cylinder (h) = 20 m. Now, Inner surface area including base (A) = .....

Given,          Height of cylinder = h = 15cm         Area of the base of the cylinder (A) = 616 cm2   Or, πr2 = 616 cm2,      where r is radius of cylinder.   Or, 3.14 ⨉ r2 .....

Given,        Radius of the base of the cylinder (r) = 7 cm        Height of the cylinder (h) = 14 cm. We know,   (i) Area of the curved surface of cylinder (CSA) = 2πrh         .....

Given,        Length of the capsule (H) = 14 mm        Diameter of the capsule (d) = 5 mm        Radius of the capsule (r) = d2                 .....

Given,        Length of the iron pipe (h) = 280 cm        Internal diameter of the iron pipe (d2) = 10 cm        Internal radius of the iron pipe (r2) = 5 cm         .....

Given,        Measure of side of the cube (l) = 50 cm We know,       Total surface area of the cube (TSAcube) = 6l2                             .....

Let r be the radius and h be the height. Given,       Area of the base of cylinder (A) = 7546 cm2 Or, πr2           = 7456 cm2 Or, 3.14 ⨉ r2 = 7456 cm2 Or, r2           .....

Given,         Diameter of the cylindrical vessel (d) = 1.4 m         Radius of the cylindrical vessel (r) = d 2 =  0.7 m         Capacity of the cylindrical vessel (V) = 770 .....

Given,        Volume of the cylindrical can (V) = 1232 cm3        Height of the cylindrical can (h) = 8 cm. We know,         Volume of a cylinder (V) = πr2h   Or, 1232 cm3 = 3.14 .....

Given,       Edge of the cube (l) = 22 cm       Height of the cylinder (h) = 11 cm. According to the question,             Area of curved surface of cylinder (CSA) = Total surface area of .....

Here,          Diameter of the cylinder (d) = 3.5 m          So , radius of the cylinder (r) = d2 = 1.75 m          Capacity of the vessel (V)     = 770 .....

Given,         Area of great circle(A) = πr2= 5cm2.         CSA of hemi-sphere = ? We have, CSA of hemisphere= 2πr2                         .....

Here,       Volume (V) = 1.54 liter=1.54 1000 cm3 = 1540 cm3       And, area of base(A) = 77 cm2 We have,        Volume = Area of base ⨉ height  Or, height  = .....

Given, Volume of the solid object (V) = 616 cm3 Height of the solid object (h) = 8 cm We know, Volume of the half of cylinder (V) = 12πr2h Or, 616 cm3 = 2214 r2  ⨉ 8cm Or, r2 = 49 cm2 Or, r  = √(49cm2 ) Or, r  = 7 .....

Given,        Height of the cylinder (h) = 1.45 m                                           = 1.45 ⨉ 100 cm     .....

Given,         External radius of the spherical ball (R) = 9 cm        Volume of the ball (V) = 2531.05 cm3. We know, Volume of the hollow sphere (V) = 43 π(R3 – r3) Or,     .....

Here,      Radius and slant height of the cone are r and l respectively. The total surface area of a cone is given by, TSA = curved surface area + area of circular .....

Given,      Diameter of the base of cylinder (d) = 70 cm      Radius of the base of cylinder (r) = d2 = 35 cm      Height of the cylinder (h) = 1 m = 100 cm. We know,       Total .....

Given,        Circumference of the base (C)  = 132 cm Or, 2πr                     = 132 cm Or, 2 ⨉ 3.14 ⨉ r      = 132 cm Or, 6.28 ⨉ r  .....

Given,          Radius of the sphere (r) = 14 cm We know,          Surface area of the sphere (TSA) = 4πr2                         .....

Given,        Diameter = d = 10.5cm        Height = h = 15.57cm        Curved surface area = ? We have,        CSA of cylinder =  2πrh = πdh    .....

Given,           Height of the cylinder (h) = 12 cm           Circumference of the base of cylinder (C) = 88 cm     Or, 2πr     = 88 cm,          .....

Here, we have given,          Circumference of the base (C) = 2πr = 88cm          Sum of radius and height (r+h)  = 24cm.          TSA of cylinder = ? Now, Total .....

Given,         Total number of circular plates (N)     = 35         Thickness of each plate (t)     = 1 cm         So, the height of the cylinder so formed (h) .....

Given,         Height of the cylinder (h) = 10 cm         Volume of the cylinder (V) = 3.85 cm3 We know,       Volume of the cylinder (V) = πr2h Or, 3.85 cm3        .....

Here,          Let  r be the radius of hemi-sphere.          Volume of the hemisphere (V) = 134.09 cm3 We know,         Volume of the hemisphere (V)    .....

Given,        Volume of the hemisphere (V) = 50.307 cm3         Let r be the radius of hemi-sphere. We know,         Volume of the hemisphere (V)     = .....

Given,          Area of the base of the hemisphere (A) = 452.57 cm2.           Let r be the radius  of hemi-sphere. We know,        Area of base of a hemisphere (A) = .....

Given,           Height of the cylinder (h) = 16 cm           Curved surface area of cylinder (CSA) = 176 cm2   Or, 2πr ⨉ h  = 176 cm2   Or, 2πr ⨉ 16 cm  = 176 .....

Here, Height = h = 7cm The total surface area of the cylinder = TSA =  1884 7 cm2 . Let r be the radius of base. Then,       TSA = 2πr2+2πrh Or, 18847  .....

Given,          Circumference of the great circle of the hemisphere (A) = 44 cm    Or, 2πr     = 44 cm                       where, r is .....

Here,       Radius of cone (r) = 12 cm2= 6 cm       Slant height (l) = 10 cm So,  Height of cone (h)  = √[l2 - r2]                      .....

Let x be any constant. Since the height of the cone and cylinder are in the ratio 2:3,  Height of cone = 2x Height of the cylinder = 3x According to the question,       2x + 3x = 30 Or, x = 6 cm So, Height of cone = 2x = 2 X 6 .....

Given,        Total surface area of hemisphere (TSA) = 11550 cm2.        Let r be the radius of hemi-sphere. We know,        Total surface area of hemisphere (TSA) = 3πr2   .....

Given,             Diameter (d) = 14cm.             Surface area = ? We have,            Surface area of sphere = πd2           .....

Given,          Volume of the hemisphere (V) = 4603.23 cm3 We know,        Volume of the hemisphere (V) = 23 πr3 Or,  4603.23 cm3 =23 ⨉ 227 ⨉ r3 Or,  4603.23 cm3 = .....

Given,         Radius of the base (r) = 14 cm         Height of the cylinder (h) = 20 cm We know, (i) Area of the curved surface of cylinder (CSA) = 2πrh               .....

Given,         Volume of the hemisphere (V) = 8316 cm3 We know,         Volume of the hemisphere (V) = 27 πr3  ,  r is radius of sphere. Or,   8316 cm3 = 23 ⨉ 227 ⨉ .....

Let r be the radius of sphere. Given,           Total surface area of the sphere (TSA) = 201.14 cm2 Or,    4πr2 = 201.14 cm2 or,      πr2 = 50.285cm2. Again,       Total .....

Given,         Length of the pipe (h) = 12 cm         Outer radius of the pipe (r1) = 2 cm.        Inner radius of the pipe (r2) = 1 cm. We know,    Total surface area of the .....

Let r be the radius of sphere. Given, Volume of the sphere (V) = 33.52 cm3 We know,       Volume of sphere (V) = 43 πr3 Or, 33.52 cm3 = 43 ⨉ 227 ⨉ r3 Or, 33.52 cm3 = 8821 ⨉ r3 Or, 33.52 cm3 ⨉ .....

Given,         Radius of 1st sphere (r1) = 1 cm So, volume of 1st sphere (V1) = 43 πr13                                       .....