Students and Teachers Forum
Given, Rate of population growth in first year (R1) = 2% Rate of population growth in second year (R2) = 2.5% Rate of population decrement in third year (R3) = .....
Given, Population of a village some years ago (P) = 200000 Population of the village now (PT) = 21632 Growth rate of the population (R) = .....
Here, Original price (P) = Rs.10000 Rate (R) = 10% Time (T) = 1 year We know, Value of machine after one year = Rs. 10000 - 10% of Rs.10000 .....
Given, Time (T) = 2 years Population before 2 years (P) = 252000 Rate of population growth in first year (R1) = 3% Rate of population .....
Given, Present cost of bicycle (P) = Rs. 3240 Rate of compound depreciation (R) = 5% p.a. Time (T) = 1 year Cost after one year (DT) = .....
Given, Rate of depreciation (R) = 15% Selling price of the motorcycle (DT) = Rs. 97750 Time (T) = 1 year Original price (P) = ? We .....
Given, Cost price of the tempo (P) = Rs. 240000 Profit earned = Rs. 48600 Time period (T) = 2 years Rate of depreciation (R) = 8% We .....
Given, Cost price of the camera (P) = Rs. 48000 Depreciated price of the bus (DT) = Rs. 34680 Rate of depreciation (R) = 15% .....
Given, Initial population (P) =185220 Time (T) = 3 years Growth rate (R) = 5% Population after 3 years (PT) = ? We have, .....
Given, Initial population of village (P) = 1250 Time period (T) = 2 years Rate of growth (R) = 2.5% Present population (PT) = ? We .....
Given, Initial population = 6400 Time = 1 year Growth rate = 5%. Now, Population after one year = 6400 + 5% of 6400 .....
Given, Original population (P) = 7200 Percentage of people migrated out = 5% Percentage of people died = 2% So, Depreciation rate(R) = 5% + 2% .....
Given, Population of the village one year ago = 10000 Population of the village at present = 9790 Population decreasing rate = ? Here, Decrease in population = 10000 - 9790 .....
Here, Initial cost of bicycle (P) = Rs. 3000 Rate of depreciatin (R) = 30% Amount of Depreciation = ? We know, PT = P (1 + R100)T = 3000 ( 1 - 30100)1 = .....
Let the sum be Rs. P. Then, Time (T) = 2 years Rate (R) = 10% p.a. Principal (P) = ? Compound Interest (CI) = ? According to the question, Compound interest (CI) – Simple interest (SI) = 240 We know, Compound interest (CI) = P [(1 + R100)T .....
Given, Principal (P) = Rs.12500 Time (T) = 2 years Rate for first year (R1) = 6% Rate for second year (R2) = 5% Compound amount (CA) = ? .....
Given, Sum of money lent to Krishna and Sundar = Rs. 5000 Time period (T) = 2 years Let the sum of money invested to Krishna and Sundar be Rs.x and Rs. (5000 – x) respectively. Then, For Krishna, Principal (P) = Rs. x Rate (R) = .....
Let the sum be Rs. P. Rate (R) = 12% Time (T) = 2 years Principal (P) = ? Simple interest (SI) =? Compound interest (CI) = ? According to question, Compound interest (CI) – .....
Given, Principal (P) = Rs.10,000 Time (T) = 2 years Rate (R) = 10% p.a. Then, Simple interest (SI) = PTR100 .....
Let the sum of money be Rs. x. According to question, When, Time (T1) = 2 years Amount (A1) = Rs. 6050 We know, Amount (A1) = P (1 + R100)T1 Or, 6050 = x (1 + R100)2 .....
Given, Simple interest (SI) = Rs. 200 Rate (R) = 5% p.a. Time (T) = 2 years We know, SI = PTR100 Or, 200 .....
Given, For A, Principal (P) = Rs.25000 Time (T) = 3 years Rate (R) = 12% We know, Simple interest (SI) = PTR100 .....
Given, Principal (P) = Rs. 640 Compound amount (CA) = Rs. 1250 Time (T) = 3 years Rate of interest (R) = ? We .....
Given, Principal (P) = Rs.7500 Time (T) = 2 years Rate of interest (R) = 10% Difference between SI and CI = .....
Given, Principal (P) = Rs. 2500 Compound amount (CA) = Rs. 3600 Rate of interest (R) = 20% Time period (T) = ? We know, .....
Given, Principal (P) = Rs. 50000 Time (T) = 3 years Rate for 1st year (R1) = 3% Rate for 2nd year (R2) = 4% Rate for 3rd year (R3) = 5% We .....
Given, Principal (P) = Rs. 5120 Compound amount (CA) = Rs.7290 Time (T) = 1 ½ years = 1.5 years We know, For interest compounded half yearly, Compound amount (CA) = P (1 + R200)2T .....
Given, Principal (P) = Rs. 8000 Compound Amount (CA) = Rs.8820 Time (T) = 2 years Rate of interest (R) = ? We know, Compound amount (CA) = P (1 + R100)T Or, .....
Here, Let the sum be Rs. P. Rate (R) = 10% Time (T) = 2 years According to question, Compound interest (CI) – Simple .....
Given, Principal (P) = Rs. 6400 Time (T) = 2 years Rate for 1st year (R1) = 5% Rate for 2nd year (R2) = 10% We know, Compound Amount (CA) = P (1 + R1100) (1 + .....
Let the sum be Rs. P. Rate (R) = 8% Time (T) = 2 years According to question, Compound interest (CI) – Simple interest (SI) = Rs.128 Or , P [(1 + R100)T - 1] - .....
Here, Time = T, Rate = r Sum = P The relation between P, T, r and CI is given by, CI= P[(1 + R100)T -1], which is the required .....
Given, Sum (P) = Rs.2000 Time (T) = 3 yrs Rate (R) = 10% Simple interest (SI) = ? We know, Simple interest = PTR100 = Rs. 2000 ⨉ 3 ⨉ .....
Given, Rate of depreciation (R) = 8% Time (T) = 3 years Value of share at present (DT) = Rs. 48668 We know, DT = P (1 - R100)T Or, 48668 = P (1 - .....
Given, Principal (P) = Rs. 12000 Rate of interest (R) = 8% p.a Time (T) = 2 years Compound amount (CA) = ? .....
Here, For time period (T) =1 year, simple interest (SI) is given by, SI = PR100 And, Compound interest (CI) = P [(1+R100) -1] .....
Given, Compound interest (CI) = Rs. 450 when time (T) = 1 year Compound interest (CI) = Rs. 945 when time (T) = 2 years Let the sum be x and the rate be r. Then , CI = P[ (1 + R100)T - 1 ] From the 1st case, 450 = x [(1+r100 ) - 1 .....
Here, Principal amount (P) = Rs. 150000 Time period (T) = 3 years Now, Compound interest received semi-annually by Prativa at 10% is given by, .....
Given, Compound amount (CA) = Rs. 6050 when Time (T) = 2 years Compound amount (CA) = Rs. 6655 when Time (T) = 3 years Sum of money (P) = ? Let the sum be ‘x’ and the interest be ‘r’ So, from the 1st case, .....
Here, Principal amount (P) = Rs. 2500, Rate of interest (R) = 8% and Time (T) = 2 years Compound Amount (CA) = ? CA = P(1+R100)T = 2500(1+8100)2 = 2500(1.08)2 .....
Here, Principal amount (P) = Rs. 80000 Time period (T) = 2 years i. 12% annually compound interest is given by, CI1 = P1+R100T-1 =Rs. 80000 .....
Given, Principal (P) = Rs.1500 Compound interest (CI) = Rs. 196.50 Rate (R) = 20% Time period (T) = ? We know, For .....
Here, Principal amount (P) = Rs. 24000 Rate of interest(R) = 12.5% Time period (T) = 3 years Now, Simple interest = PTR100 .....
Let the sum be Rs. P. Then, Time (T) = 2 years Rate (R) = 5% p.a. Principal (P) = ? Compound interest (CI) = ? According to the question, Compound interest (CA) – Simple interest (SI) = 120 We know, Compound interest (CI) = P [(1 + R100)T .....
Here, Principal amount = P (say) Interest rate (R) = 5% Time period(T) = 4 years Amount of sum borrowed (P) = ? From question, Profit = Rs. .....
Here, Let the amount lent to Ram is Rs.x. Then, Time (T) = 2 years Rate of interest (R) = 15% We know, Simple interest (SI) = PTR100 = x .....
Here, Amount = A Rate percent per annum = r Time period = T Then, the principal is given by, P = A / (1+ r / .....
Given, Rate of interest (R) = 5% p. a. Time (T) = 2 years Compound Amount (CI) = Rs.82.41. Sum invested (P) = ? We know, .....
Given, Principal (P) = Rs. 8000 Compound Amount (CA) = Rs. 8820 Time (T) = 2 years Rate of interest (R) = ? We know, .....
Let the sum of money be Rs. x. According to question, When, Time (T1) = 2 years Amount (A1) = Rs. 7260 We know, Amount (A1) = P (1 + R100)T1 Or, 7260 = x (1 + R100)2 .....