Students and Teachers Forum

Given,        Rate of population growth in first year (R1) = 2%        Rate of population growth in second year (R2) = 2.5%        Rate of population decrement in third year (R3) = .....

Given,           Population of a village some years ago (P) = 200000           Population of the village now (PT) = 21632           Growth rate of the population (R) = .....

Here,     Original price (P) = Rs.10000     Rate (R) = 10%     Time (T) = 1 year We know,       Value of machine after one year = Rs. 10000 - 10% of Rs.10000             .....

Given,        Time (T) = 2 years         Population before 2 years (P) = 252000         Rate of population growth in first year (R1) = 3%         Rate of population .....

Given,        Present cost of bicycle (P) = Rs. 3240        Rate of compound depreciation (R) = 5% p.a.        Time (T) = 1 year        Cost after one year (DT) = .....

Given,         Rate of depreciation (R) = 15%         Selling price of the motorcycle (DT) = Rs. 97750         Time (T) = 1 year         Original price (P) = ? We .....

Given,         Cost price of the tempo (P) = Rs. 240000         Profit earned = Rs. 48600         Time period (T) = 2 years         Rate of depreciation (R) = 8% We .....

Given,          Cost price of the camera (P) = Rs. 48000          Depreciated price of the bus (DT) = Rs. 34680          Rate of depreciation (R) = 15%       .....

Given,         Initial population (P) =185220         Time (T) = 3 years         Growth rate (R) = 5%         Population after 3 years (PT) = ? We have,    .....

Given,         Initial population of village (P) = 1250         Time period (T) = 2 years         Rate of growth (R) = 2.5%         Present population (PT) = ? We .....

Given,         Initial population = 6400         Time = 1 year         Growth rate = 5%. Now,          Population after one year = 6400 +  5% of 6400   .....

Given,      Original population (P) = 7200      Percentage of people migrated out = 5%      Percentage of people died = 2% So,         Depreciation rate(R) = 5% + 2%   .....

Given, Population of the village one year ago = 10000 Population of the village at present = 9790 Population decreasing rate = ? Here, Decrease in population = 10000 - 9790                     .....

Here, Initial cost of bicycle (P) = Rs. 3000 Rate of depreciatin (R) = 30% Amount of Depreciation = ? We know, PT = P (1 + R100)T       = 3000 ( 1 - 30100)1       = .....

Let the sum be Rs. P. Then, Time (T) = 2 years Rate (R) = 10% p.a. Principal (P) = ? Compound Interest (CI) = ? According to the question, Compound interest (CI) – Simple interest (SI) = 240 We know, Compound interest (CI) = P [(1 + R100)T .....

Given,       Principal (P) = Rs.12500       Time (T) = 2 years       Rate for first year (R1) = 6%       Rate for second year (R2) = 5%       Compound amount (CA) = ?   .....

Given, Sum of money lent to Krishna and Sundar = Rs. 5000 Time period (T) = 2 years   Let the sum of money invested to Krishna and Sundar be Rs.x and Rs. (5000 – x) respectively. Then,  For Krishna, Principal (P) = Rs. x Rate (R) = .....

Let the sum be Rs. P. Rate (R) = 12% Time (T) = 2 years Principal (P) = ? Simple interest (SI) =? Compound interest (CI) = ?  According to question,                   Compound interest (CI) – .....

Given,       Principal (P) = Rs.10,000      Time (T) = 2 years       Rate (R) = 10% p.a. Then, Simple interest (SI) = PTR100                       .....

Let the sum of money be Rs. x. According to question, When, Time (T1) = 2 years Amount (A1) = Rs. 6050 We know, Amount (A1) = P (1 + R100)T1        Or, 6050 = x (1 + R100)2 .....

Given,      Simple interest (SI) = Rs. 200      Rate (R) = 5% p.a.      Time (T) = 2 years We know,            SI = PTR100            Or, 200 .....

Given, For A,        Principal (P) = Rs.25000        Time (T) = 3 years        Rate (R) = 12% We know, Simple interest (SI) = PTR100                 .....

Given,          Principal (P) = Rs. 640          Compound amount (CA) = Rs. 1250          Time (T) = 3 years          Rate of interest (R) = ? We .....

Given,          Principal (P) = Rs.7500          Time (T) = 2 years          Rate of interest (R) = 10%          Difference between SI and CI = .....

Given,        Principal (P) = Rs. 2500        Compound amount (CA) = Rs. 3600        Rate of interest (R) = 20%        Time period (T) = ? We know,       .....

Given,      Principal (P) = Rs. 50000      Time (T) = 3 years      Rate for 1st year (R1) = 3%      Rate for 2nd year (R2) = 4%      Rate for 3rd year (R3) = 5% We .....

Given, Principal (P) = Rs. 5120 Compound amount (CA) = Rs.7290 Time (T) = 1 ½ years                = 1.5 years We know, For interest compounded half yearly, Compound amount (CA) = P (1 + R200)2T   .....

Given, Principal (P) = Rs. 8000 Compound Amount (CA) = Rs.8820 Time (T) = 2 years Rate of interest (R) = ? We know, Compound amount (CA) = P (1 + R100)T         Or,                  .....

Here,        Let the sum be Rs. P.        Rate (R) = 10%        Time (T) = 2 years According to question,             Compound interest (CI) – Simple .....

Given,       Principal (P) = Rs. 6400       Time (T) = 2 years       Rate for 1st year (R1) = 5%      Rate for 2nd year (R2) = 10% We know, Compound Amount (CA) = P (1 + R1100) (1 + .....

Let the sum be Rs. P. Rate (R) = 8% Time (T) = 2 years According to question,               Compound interest (CI) – Simple interest (SI) = Rs.128        Or , P [(1 + R100)T - 1] - .....

Here, Time = T, Rate = r  Sum = P The relation between P, T, r and CI is given by,   CI= P[(1 + R100)T -1], which is the required .....

Given, Sum (P) = Rs.2000 Time (T) = 3 yrs Rate (R) = 10% Simple interest (SI) = ? We know, Simple interest =  PTR100                           = Rs. 2000 ⨉ 3 ⨉ .....

Given,        Rate of depreciation (R) = 8%        Time (T) = 3 years        Value of share at present (DT) = Rs. 48668 We know,       DT = P (1 - R100)T Or, 48668 = P (1 - .....

Given,         Principal (P) = Rs. 12000         Rate of interest (R) = 8% p.a         Time (T) = 2 years         Compound amount (CA) = ?         .....

Here,   For time period (T) =1 year, simple interest (SI) is given by,   SI = PR100 And,         Compound interest (CI)  = P [(1+R100) -1]             .....

Given, Compound interest (CI) = Rs. 450 when time (T) = 1 year  Compound interest (CI) = Rs. 945 when time (T) = 2 years Let the sum be x and the rate be r. Then , CI = P[ (1 + R100)T - 1 ] From the 1st case, 450 = x [(1+r100 ) - 1 .....

Here,        Principal amount (P) = Rs. 150000        Time period (T) = 3 years Now,           Compound interest received semi-annually by Prativa at 10% is given by,     .....

Given, Compound amount (CA) = Rs. 6050 when Time (T) = 2 years Compound amount (CA) = Rs. 6655 when Time (T) = 3 years Sum of money (P) = ? Let the sum be ‘x’ and the interest be ‘r’ So, from the 1st case,     .....

Here, Principal amount (P) = Rs. 2500, Rate of interest (R) = 8% and Time (T) = 2 years Compound Amount (CA) = ? CA = P(1+R100)T        = 2500(1+8100)2         = 2500(1.08)2        .....

Here,        Principal amount (P) = Rs. 80000        Time period (T) = 2 years i. 12% annually compound interest is given by,     CI1 = P1+R100T-1            =Rs. 80000 .....

Given,        Principal (P) = Rs.1500        Compound interest (CI) = Rs. 196.50        Rate (R) = 20%        Time period (T) = ? We know,      For .....

Here,        Principal amount (P) = Rs. 24000        Rate of interest(R) = 12.5%        Time period (T) = 3 years Now, Simple interest = PTR100             .....

Let the sum be Rs. P. Then, Time (T) = 2 years Rate (R) = 5% p.a. Principal (P) = ? Compound interest (CI) = ? According to the question, Compound interest (CA) – Simple interest (SI) = 120 We know, Compound interest (CI) = P [(1 + R100)T .....

Here,      Principal amount = P (say)      Interest rate (R) = 5%     Time period(T) = 4 years     Amount of sum borrowed (P) = ? From question,           Profit = Rs. .....

Here, Let the amount lent to Ram is Rs.x. Then, Time (T) = 2 years Rate of interest (R) = 15% We know, Simple interest (SI) = PTR100                                 = x .....

Here, Amount = A Rate percent per annum = r Time period = T Then, the principal is given by, P = A / (1+ r / .....

Given,         Rate of interest (R) = 5% p. a.         Time (T) = 2 years         Compound Amount (CI) = Rs.82.41.         Sum invested (P) = ? We know,     .....

Given,          Principal (P) = Rs. 8000         Compound Amount (CA) = Rs. 8820         Time (T) = 2 years         Rate of interest (R) = ? We know,     .....

Let the sum of money be Rs. x. According to question, When,     Time (T1) = 2 years Amount (A1) = Rs. 7260 We know, Amount (A1) = P (1 + R100)T1 Or, 7260 = x (1 + R100)2 .....